63x=16x^2-16x+20x-20

Solution for 63x=16x^2-16x+20x-20 equation:

63x=16x^2-16x+20x-20

We move all terms to the left:

63x-(16x^2-16x+20x-20)=0

We get rid of parentheses

-16x^2+63x+16x-20x+20=0

We add all the numbers together, and all the variables

-16x^2+59x+20=0

a = -16; b = 59; c = +20;
Δ = b2-4ac
Δ = 592-4·(-16)·20
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-69}{2*-16}=\frac{-128}{-32}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+69}{2*-16}=\frac{10}{-32}
=-5/16
$